Hi!!
$dbQuery = "select * from table where 1" ;
$result = mysql_query($dbQuery) or die("Error trying to execute the query:
".mysql_error());
If(mysql_num_rows($result)<1){ //also: "==0" works
echo "NULL";
-----Original Message-----
From: Kane Wilson [mailto:[EMAIL PROTECTED]
Sent: Wednesday, September 07, 2005 1:40 AM
To: mysql
Subject: please help .........very urgent
hi ,
I wanted to check the following condition and if it is success i wanted to
display a massage.I tried as follows. but no luck. nothing displayed.
$dbQuery = results;
$result = mysql_query($dbQuery) or die("Couldn't get file list");
if (!isset($result))
{echo "NULL";}
//if (mysql_result($result == 0))(
//echo "sorry";
?>
please , tell me how can i do this ?
Thanx
Kane.
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