----- Original Message -----
From: [EMAIL PROTECTED]
To: Barry
Cc: [email protected]
Sent: Monday, October 03, 2005 9:49 PM
Subject: Re: Query Trouble!
"Barry" <[EMAIL PROTECTED]> wrote on 10/03/2005 04:38:48 PM:
> I'm new to MySQL and am using version 4-1-12a on my development
> machine locally this query works just fine:
>
> SELECT * FROM actor
> WHERE id IN
> ( SELECT id FROM episode_cast
> WHERE episode_number =001)
>
> but when I try to run it from the web server which is running version
> 4.0.24-standard I get an error:
>
> #1064 - You have an error in your SQL syntax. Check the manual that
> corresponds to your MySQL server version for the right syntax to use
> near 'SELECT id from episode_cast WHERE episode_number = 001
>
> I put this together from a book that's at least 2 years old so I
> wouldn't have thought that it was because of different versions, but I
> could well be wrong!
>
> Any help would be much appreciated.
>
Well, Barry, the book was written towards 4.1 as that is the first version
with subqueries. You will need to convert your SQL into the JOIN-form like
this:
SELECT a.*
FROM actor a
INNER JOIN episode_cast e
on e.id = a.id
WHERE e.episode_number = 001;
That will work on all versions :-)
Shawn Green
Database Administrator
Unimin Corporation - Spruce Pine
Thanks for that Shawn it works a treat.
I have just spent the last three hours reading about joins and subquerys in
the manual and I'm still no clearer on how they work..
Barry
