On Sun, 12 Mar 2006, Michael Stassen wrote: > To: [EMAIL PROTECTED] > From: Michael Stassen <[EMAIL PROTECTED]> > Subject: Re: Checking for good update > > [EMAIL PROTECTED] wrote: > > looks a bit strange to me. > > > > > $result = mysql_query($query) or die('Query couldn\'t > > > executed:'.mysql_error()); > > > > please try something like this: > > Why? There's nothing wrong with the above statement.
I've never seen logic like that before. It looks to me like fbsd_user is trying to use the OR operator outside an if statement. Is the mentioned in the php manual somewhere Michael? > > I've not tested this - but it looks like you are mixing sending the > > mysql query and testing for the result of the query at the same time, > > which AFAIK is not possible. > > You should try it. It works just fine, and isn't the problem. The > problem is that you cannot treat the result of an UPDATE as if it were a > SELECT. Regards Keith Roberts -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe: http://lists.mysql.com/[EMAIL PROTECTED]