Hi Renish, Here's the answer for your query.
mysql> select * from a; +--------+ | item | +--------+ | book | | pencil | | table | | chair | +--------+ mysql> select * from b; +--------+-----------+ | item | price | +--------+-----------+ | pencil | 11 dollar | | book | 12 dollar | +--------+-----------+ You can use this query to get the items which doesnt have price. mysql> select item from a where item not in ( select item from b); +-------+ | item | +-------+ | table | | chair | +-------+ Thanks, ViSolve DB Team. ----- Original Message ----- From: "Renish" <[EMAIL PROTECTED]> To: <mysql@lists.mysql.com> Sent: Monday, November 27, 2006 8:45 AM Subject: MySql doubt. > Hi Guys, > > I have an easy doubt.. > > Table A consist of field Item and Table B consist of field Price. Table A > consists of Items which has price aswell the items which doesnt have price. > But In Table B,I have kept only the item which has price . Now, I want to > subtract the total items in Table A to the total items in Table B. so I get > the items which doesnt have price. I used union its not working.. can any of > u guys write the code for it,,, > > For example > > Table A > Item Book > Pencil > Table > Table B- which consists of Item with price > > Price -Book-11 dollar > Pencil-2 dollar > > Please reply me asap. I hope it should be v. easy enough to tackle. > > Cheers, > Renish koshy > > > -- > MySQL General Mailing List > For list archives: http://lists.mysql.com/mysql > To unsubscribe: http://lists.mysql.com/[EMAIL PROTECTED] >
