There's probably something wrong with your PHP code. It should look something
like...
$result = mysql_query("select count(*) as cnt from table") or die
(mysql_error());
$row = mysql_fetch_array($result);
$count = $row[cnt];
print $count;
Sounds like you're doing something more like:
$result = mysql_query("select count(*) as cnt from table") or die
(mysql_error());
print $result;
On Monday 26 November 2001 03:43 pm, Cory Gagliardi wrote:
> I'm using PHP with mySQL and I got very weird results when I ran a count.
> I used "SELECT COUNT(*) FROM $TableName", with $TableName being my table's
> name, for the Query. When I printed the result I got "Resource id #2",
> what does that even mean. And what did I do wrong?....
>
>
> ---------------------------------------------------------------------
> Before posting, please check:
> http://www.mysql.com/manual.php (the manual)
> http://lists.mysql.com/ (the list archive)
>
> To request this thread, e-mail <[EMAIL PROTECTED]>
> To unsubscribe, e-mail
> <[EMAIL PROTECTED]> Trouble
> unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php
---------------------------------------------------------------------
Before posting, please check:
http://www.mysql.com/manual.php (the manual)
http://lists.mysql.com/ (the list archive)
To request this thread, e-mail <[EMAIL PROTECTED]>
To unsubscribe, e-mail <[EMAIL PROTECTED]>
Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php
