Hello
I've got a problem selecting values that match an option from a SET column.
My two columns are set up as follows:
res_places SET('North','West','South')
res_places_re SET('Aber','Cardiff','Bangor')
And I'm currently using the following MySQL query:
SELECT * FROM gd_records WHERE (res_places & 3) AND (res_places_re
& 1);
Which turns out very strange resutls.
What I'm trying to do (in english) is to select records from the database
which matches option 3 in SET column res_places AND matches option 1 in SET
column res_places_re.
For some reason my SQL query does not give me the desired results. I know
that a record matches both these criteria but yet this omits that record
when returning result.
Is the SQL query I am using correct? Is this the correct way of going about
what I'm trying to do? I don't want to use FIND_IN_SET because I won't
always know the SET option name to pass to FIND_IN_SET.
Thanks for your help.
Wiliam Stephens
Web Developer
http://www.fbagroup.co.uk
---------------------------------------------------------------------
Before posting, please check:
http://www.mysql.com/manual.php (the manual)
http://lists.mysql.com/ (the list archive)
To request this thread, e-mail <[EMAIL PROTECTED]>
To unsubscribe, e-mail <[EMAIL PROTECTED]>
Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php
