Try using "LIKE" instead of "=":
$sth = $dbh->prepare("SELECT * FROM Years WHERE Date LIKE '2002-%'");
$sth->execute();
On Wed, 2002-01-23 at 17:09, Jason Whitlow wrote:
>
> I am trying to do a select statement but am having problems with the "%" in
> my string.
>
> I am trying to
>
> $sth = $dbh->prepare("SELECT * FROM Years WHERE Date = '2002-%'");
> $sth->execute();
>
> I just get nothing. No Error messages, nothing. All other sql statements
> work just fine. Is it something with the mysql.pm in regardes to the %
> sign??
>
>
> Thanks for any help.
>
> Jason
>
> Senior Network Engineer
> Jason Whitlow
> wk-714-384-3456
> cell-714-412-7299
> 1221 E. Dyer Suite 150
> Santa Ana, CA. 92705
>
>
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--
Diana Soares
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