While this should be on the PHP list, here's the problem. You're not doing a
printf or whatever function that is that replaces %s with values - you're
just assigning the string to $retval. It should look something like:
$retval .= printf(" ...yadayada");
look up the syntax - I never use printf, so mine is probably wrong, but
that's the problem.
- Jonathan
-----Original Message-----
From: Alex Behrens [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, April 02, 2002 1:46 PM
To: [EMAIL PROTECTED]
Subject: need some help...
Hey Guys,
I need help indentifiying why I have an error in this line of syntax:
while($a=mysql_fetch_array($r)) {
$retval.=" <a href=\"%s\"><img src=\"%s\"
border=\"0\"></a><br> - <a
href=\"%s\">%s</a><br><br>",$a["url"],$a["picurl"],$a["url"],$a["title"])";
}
It just gives me a parse error on the page for the $retval. = line
Thanks!
--------------------------------------------
-Alex "Big Al" Behrens
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