Hi again
I'm getting this message now:
Supplied argument is not a valid MySQL result resource ..at the 4th line.
What could be the problem now?
Thx again
function AddItem($OrderID,$ProductID,$Qty)
{
$Datasource = new Datasource;
$result = mysql_query("Select Count(*) FROM orderitemdetail WHERE
Product_Id=$ProductID AND Order_Id=$OrderID");
$row = mysql_fetch_row($result);
if ($row[0]>0)
{
$SQL1 = "UPDATE orderitemdetail SET Quantity=Quantity+$Qty ".
" WHERE Product_Id=$ProductID AND Order_Id=$OrderID";
}
else
{
$SQL1 = "INSERT INTO orderitemdetail (Order_Id, Product_Id, Quantity)".
"VALUES($OrderID,$ProductID,1)";
}
$QueryResult = $Datasource->QueryDatasource($SQL1);
return $QueryResult;}
}
---------------------------------------------------------------------
Before posting, please check:
http://www.mysql.com/manual.php (the manual)
http://lists.mysql.com/ (the list archive)
To request this thread, e-mail <[EMAIL PROTECTED]>
To unsubscribe, e-mail <[EMAIL PROTECTED]>
Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php