Hi,
Nice tricky, but...
SET @x:=0;
SELECT @x:=t1.id+1 FROM mytable t1 LEFT JOIN mytable t2 ON t1.id+1 = t2.id
WHERE t2.id IS NULL LIMIT 1;
INSERT INTO mytable SET id=@x,data0='xxxxxxxxx',data1='yyyyyyyy';
Regards,
Gelu
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G.NET SOFTWARE COMPANY
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----- Original Message -----
From: Dan Nelson <[EMAIL PROTECTED]>
To: daniel <[EMAIL PROTECTED]>
Cc: <[EMAIL PROTECTED]>
Sent: Friday, May 03, 2002 1:24 AM
Subject: Re: inserting into the lowest possible id
> In the last episode (May 02), daniel said:
> > lets say you have a table like this
> >
> > id | data0 | data1 | ...
> > 0 | xxxxx | yyyyy | ...
> > 1 | xxxxx | yyyyy | ...
> > 2 | xxxxx | yyyyy | ...
> > 3 | xxxxx | yyyyy | ...
> > 4 | xxxxx | yyyyy | ...
> > 7 | xxxxx | yyyyy | ...
> >
> > what if when i performed an INSERT query again, i wanted that id to
> > NOT be 8, but be 5 since it's the lowest available id. what would i
> > do?
>
> SELECT t1.id+1
> FROM mytable t1 LEFT JOIN mytable t2 ON t1.id+1 = t2.id
> WHERE t2.id IS NULL;
>
> That will return the first "empty" id in each block of unused ids. In
> your example, it would return
>
> +---------+
> | t1.id+1 |
> +---------+
> | 5 |
> | 8 |
> +---------+
> 2 rows in set
>
> If you only want the first row, add a "LIMIT 1" to the end of the query.
>
> --
> Dan Nelson
> [EMAIL PROTECTED]
>
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