Thanks for the quick response. The times are stored in TIME format. If I 
do the following:

SELECT *, time_out-time_in as job_time from time_sheet;

the job_time column gives me the right time, but is not formatted, for 
example:

time_in = 11:00
time_out = 13:15

job_time= 21500

Any pointers?

-Chris

On Saturday, August 10, 2002, at 09:36 AM, DL Neil wrote:

> Hello Christopher,
>
>> I need to ask for some help and I can't find anything in the manuals. I
>> am writing a php based app that as one of it's functions keeps an
>> employee time sheet. The times are stored in a mysql database with 2
>> columns - time_in and time_out. What I need to do is subtract these to
>> columns to show a job_time (which should be in hh:mm form).
>>
>> Can anyone give me any suggestions? Or am I better off doing this on 
>> the
>> PHP side rather than the mysql side?
>
>
> My general rule is that when pulling data out of an RDBMS it is best to 
> do
> as much as possible there, than to transfer data into (say) PHP and
> post-process it.
>
> Are the times stored as DATETIME/TIME, timestamp, or other format data? 
> The
> answer will thus vary! Assuming we're not talking about timestamps 
> (trivial
> exercise) then SEC_TO_TIME() and its counterpart may be of interest. 
> Manual
> ref: http://www.mysql.com/doc/en/Date_and_time_functions.html
>
> Regards,
> =dn
>
>
>
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