Ah....
Never mind, i got it. I did some stupid stuff, but figured it out. Here's
the working query:
SELECT title, authorName, journalName, journalPages, aname, tname,
avg(ranking)
FROM publications LEFT OUTER JOIN ranking ON (publications.pubID =
ranking.pubID),
area, topic, pubTopicInt
WHERE publications.areaID = area.areaID
AND
publications.pubID = pubTopicInt.pubID
AND
topic.topicID = pubTopicInt.topicID
AND
publications.pubID = 7
GROUP BY (publications.pubID);
Thanks for your patience.
Desmond
>From: "Desmond Lee" <[EMAIL PROTECTED]>
>To: [EMAIL PROTECTED]
>Subject: help with syntax of left outer join
>Date: Tue, 13 Aug 2002 14:34:06 -0700
>
>Hi there
>
>
>I want to do a left outer join but i also have a bunch of where conditions
>in my sql statment that i need. Can anyone help me out:
>
> SELECT title, authorName, journalName, journalPages, aname, tname,
>avg(ranking)
> FROM publications, area, topic, pubTopicInt,
> LEFT OUTER JOIN ranking publications.pubID = ranking.pubID
> WHERE publications.areaID = area.areaID
> AND
> publications.pubID = pubTopicInt.pubID
> AND
> topic.topicID = pubTopicInt.topicID
> AND
> publications.pubID = ranking.pubID
> AND
> publications.pubID = 3
> GROUP BY (publications.pubID);
>
>I look at the mysql documentation, but i couldn't really understand their
>examples when they had additional where cluases.
>
>THanks
>
>
>Desmond
>
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