Let's try this :
$qid = mysql_query("SELECT * FROM 1_nodedata WHERE id='$edit_id'") or
die(mysql_error());
----- Original Message -----
From: "Anil Garg" <[EMAIL PROTECTED]>
To: "Jocelyn Fournier" <[EMAIL PROTECTED]>; <[EMAIL PROTECTED]>
Sent: Thursday, August 15, 2002 11:42 PM
Subject: Re: Supplied argument is not a valid MySQL result resource!!
> yes..it echos $edit_id fine.
> i am also feeling strange why its not working!
> regards
> anil
> ----- Original Message -----
> From: "Jocelyn Fournier" <[EMAIL PROTECTED]>
> To: "Anil Garg" <[EMAIL PROTECTED]>; <[EMAIL PROTECTED]>
> Sent: Thursday, August 15, 2002 5:40 PM
> Subject: Re: Supplied argument is not a valid MySQL result resource!!
>
>
> > Hi,
> >
> > try :
> >
> > > $qid = mysql_query("
> > > SELECT *
> > > FROM 1_nodedata
> > > WHERE id = '$edit_id'
> > > ");
> > > $frm = mysql_fetch_array($qid);
> >
> > (what does echo "edit_id : $edit_id"; display ?)
> >
> > Regards,
> > Jocelyn
> > ----- Original Message -----
> > From: "Anil Garg" <[EMAIL PROTECTED]>
> > To: <[EMAIL PROTECTED]>
> > Sent: Thursday, August 15, 2002 11:12 PM
> > Subject: Supplied argument is not a valid MySQL result resource!!
> >
> >
> > > Hi,
> > > in the piece of code given below
> > > -----------
> > > $qid = mysql_query("
> > > SELECT *
> > > FROM 1_nodedata
> > > WHERE id = $edit_id
> > > ");
> > > $frm = mysql_fetch_array($qid);
> > > -----------
> > > i get the follownig error:
> > >
> > > Warning: Supplied argument is not a valid MySQL result resource in
> > > /z/mercury/www/niksun/admin/add_doc.php on line 107
> > > element type:
> > >
> > > What is it happening so!!
> > > regards
> > > anil
> > >
> > >
> > > ---------------------------------------------------------------------
> > > Before posting, please check:
> > > http://www.mysql.com/manual.php (the manual)
> > > http://lists.mysql.com/ (the list archive)
> > >
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> > >
> > >
> > >
> >
>
>
>
>
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