Hi

Just try this

select distinct(a.id) from test a , test b where a.code = 23 and b.code = 45
and a.id = b.id

Regards,
-Arul
----- Original Message -----
From: "Robert Gehrig" <[EMAIL PROTECTED]>
To: "MySQL List" <[EMAIL PROTECTED]>
Sent: Wednesday, December 04, 2002 10:52 PM
Subject: Select Problem


> Hi all
>
> I have a detail table that has multiple records associated with an ID
number
> Both fields are integers
>
> E.G.
>
> Id Code
> 4 23
> 4 27
> 34 23
> 34 45
> 34 28
>
> What I need to find is the Id where the code is 23 and 45 for the same Id
(the result in this case would be 34)
>
> How do I do this with a SQL query
>
> Thanks
>
> Robert Gehrig
> Webmaster at www.gdbarri.com
>
> e-mail: [EMAIL PROTECTED]
>
>
>
>
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