http://www.mysql.com/doc/en/JOIN.html
mysql> SELECT table1.* FROM table1
-> LEFT JOIN table2 ON table1.id=table2.id
-> WHERE table2.id IS NULL;
So...
Select n.uid, n.name from names_table n
LEFT JOIN exclude ON n.uid = exclude.n_uid
WHERE exclude.n_uid IS NULL;
-----Original Message-----
From: Michelle de Beer [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, December 11, 2002 11:22 AM
To: mysql list
Subject: Select Where !=
I have two tables. One with names and one for
excluding certain names. Exclude-table contains the
uid for the name excluded.
If I want to see which names has been excluded, this
query does the job:
Select n.uid, n.name from names_tables n, exclude
WHERE n.uid = exclude.n_uid
But if I want to select all names, but leave out the
ones that are in the "exclude"-table, I thought this
would do it, but no.
Select n.uid, n.name from names_tables n, exclude
WHERE n.uid != exclude.n_uid
It has something to do with the != thingy...
Any thoughts?
// Michelle
sql, query
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