> mysql_select_db("books");
> $query = "SELECT * FROM books WHERE ".$searchType." LIKE
> '%".$searchTerm."%'";
> $result = mysql_query($query);
>
> $num_results = mysql_num_rows($result); //This is where I am getting the
> error actually: "Warning: mysql_num_rows(): supplied argument is not a
valid
> MySQL result resource in c:\inetpub\wwwroot\php testing\results.php on
line
> 33"
Try the following after the call to mysql_query() so you can see why $result
is an invalid argument for mysql_num_rows():
echo mysql_error()."<br>\n";
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