SELECT *,s.status AS ActiveJob FROM Jobs AS j LEFT JOIN Submissions AS s ON j.job_id=s.job_id
WHERE s.status IS NULL
On Monday, July 28, 2003, at 02:37 PM, Richard Bolen wrote:
I'm trying to write a select query that involves 2 tables. One table (Submissions) has a one to many relationship with the other table (Jobs). I'm trying to find all the records in Jobs that do NOT have a corresponding record in Submissions with a status of 1.
The problem I'm having is that when there is more than one record in
Submissions that match a record in Jobs and one Submissions record has a
status of 1 and one record doesn't, my query matches the one with status
!= 1 and returns the record for Jobs (even though it has a record in
Submissions with a status of 1 also).
I've tried a variety of queries including left outer joins and more simple join relationships. I'm using MySQL 3.23.47 on Windows.
Here's an example query:
select j.job_id from jobs j left outer join submissions s on (j.job_id =
s.job_id) where s.status_id != 1 group by j.job_id
Any help is greatly appreciated.
Rich
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