That query will work. The note is just dosn't matter, when building your SQL
statment replace it with a varible. In PHP for instance you can do the
following

$IDValue = 100 ;
$Query = "SELECT id FROM myTable WHERE infoId IN (3) AND id  $IDValue ORDER
BY id  ASC LIMIT 49,1" ;

Job done. No idea why on earth you would ever want to use a nested select to
do the job in the first place. Just seems to be a waste to me. Not to
mention its probably going to be slower using nested selects then just
"ORDER BY".


----- Original Message ----- 
From: "Victoria Reznichenko" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Tuesday, September 23, 2003 2:41 PM
Subject: Re: nested select alternative??


: "Wajih-ur-Rehman" <[EMAIL PROTECTED]> wrote:
: > I have this statement that works perfectly fine in Access and MSSQL: (In
: > words, i first get the top 50 id values according to the where clause
and
: > then i get the maximum of those id values)
: >
: > "SELECT Max(id) FROM (select top 50 id from myTable  where  infoId in
: > ( 3 ) AND id > 100 order by id  ASC) AS t1 "
:
: Max id is the last row in the result set of the query "select id from
myTable  where  infoId in ( 3 ) AND id > 100 order by id  ASC LIMIT 50". So,
you can write:
:
: SELECT id FROM myTable WHERE infoId IN (3) AND id > 100 ORDER BY id  ASC
LIMIT 49,1;
:
: >
: > (Note that id > 100 changes in every iteration of the loop in my code)
:
: Sorry, this note is not clear enough for me. What do you mean?
:
: >
: > I want to run a similar query in MYSQL....Is there *any* way to
accomplish
: > it ? I have tried the following query without any luck
: >
: > "SELECT Max(id) FROM (select id from myTable  where  infoId in
: > ( 3 ) AND id > 100 order by id  ASC LIMIT 50) AS t1 "
: >
:
:  From v4.1 you can use derived table and the above query will work.
:
:
:
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