You can use RLIKE which is regular expressions then you should be able to execute
SELECT * FROM sometable WHERE surname RLIKE '^[A-C]' ORDER BY surname; Kelley Scott Brown wrote: > Hi, List, > > I looked here: > > http://www.mysql.com/doc/en/String_comparison_functions.html > > But I am not seeing what I need. > > I want to do a string comparison like this: > > SELECT * FROM sometable WHERE surname LIKE '[A-C]%' ORDER BY surname; > > This works in another RDBMS. It doesn't return a syntax error, either, but > it returns no records. My guess is that MySQL is interpreting the whole > thing literally, rather than looking for what I want. > > I need this to return all records where surname begins with the letters A > through C (that is, all records with a surname which begins with A, B, or C). > > Anybody got a how-to? I'm sure there must be some way, other than to do > this three times. Some of these can vary; that is, it may be 0-9, or 0-Z > (show all), even, so I don't want to do a bunch of OR'ing, either. > > Thanks! > --Scott Brown > > -- > MySQL General Mailing List > For list archives: http://lists.mysql.com/mysql > To unsubscribe: http://lists.mysql.com/[EMAIL PROTECTED] -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe: http://lists.mysql.com/[EMAIL PROTECTED]
