The following query produces the following results: select job_coop as 'Job/Coop', count(*) as Count from queue group by job_coop;
+----------+-------+ | Job/Coop | Count | +----------+-------+ | B03013 | 19 | | B05044 | 9 | | B07037 | 6 | | B15037 | 4 | | B16032 | 6 | | B17026 | 6 | | B17056 | 18 | | B18032 | 5 | | B20009 | 31 | | B21012 | 1 | | B24026 | 8 | | B25001 | 42 | | B27043 | 10 | | B27047 | 8 | | B29064 | 6 | | B31004 | 61 | | B36035 | 60 | | B36529 | 54 | | B38023 | 38 | | B38034 | 7 | | B40020 | 30 | | D18032 | 31 | | D27047 | 2 | | D31004 | 59 | +----------+-------+ Is there a way to use the ORDER BY clause to order the results by the numeric value of the count(*), i.e. so that the results would be sorted by the result of the count(*)? Dirk Bremer - Systems Programmer II - ESS/AMS - NISC St. Peters USA Central Time Zone 636-922-9158 ext. 8652 fax 636-447-4471 [EMAIL PROTECTED] www.nisc.cc -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe: http://lists.mysql.com/[EMAIL PROTECTED]
