I Think that all gets to
complicated!
What If I use on regex
wich extracts my from a Filename the gamename without the number
Like: Giana 01.adf
Giana02.adf Giana3.adf this function always returns Giana.
Then I Check how long
this Function Retirns the same Filename and so long it adds the files to a
field in the database with a increasing field numer like: fd0 = “giana 01.af”
fd1=”gina02.adf”…
Because I need the names
of all the disk images!
The Problem for me is
only the regex and how I implement a RegEx in C
Von: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]] Im Auftrag von Devan Lippman
Gesendet: Samstag, 21. Mai 2005
01:21
An: Jeff; Development
of mythtv
Betreff: Re: [mythtv] Programming
help.
oops,
for(int i = 1; i < match.length() && !result; i++) result
= ismatch(filename, match.substr(1));
for(int i = 0; i <
filename.length()-match.length() && !result; i++) result =
ismatch(filename.substr(i), match.substr(1));
On 5/20/05, Devan
Lippman <[EMAIL PROTECTED]>
wrote:
write a function ismatch() that will take two strings and compare them
recursivly with wildcard support. so for example a call could look
like this:
ismatch("Giana 01.adf", "Giana*.adf")
which would call itself
ismatch("iana 01.adf", "iana*.adf")
ismatch("ana 01.adf", "ana*.adf")
...
ismatch(" 01.adf", "*.adf")
and then at the wildcard call
ismatch(" 01.adf", ".adf")
ismatch("01.adf", ".adf")
ismatch("1.adf", ".adf")
ismatch(".adf", ".adf")
something like this:
bool ismatch(string filename, string match)
{
bool result = false;
if(match[0] == '*')
{
for(int i = 1; i < match.length() &&
!result; i++) result = ismatch(filename, match.substr(1));
if(match.length() == 1) return true;
}
if(match.length() == 1 && match == filename) return true;
return match[0] == filename[0] &&
ismatch(filename.substr(1), match.substr(1));
actually thats horrible, but it probably work it you convert it from my
made up language to C++.
On 5/20/05, Jeff <[EMAIL PROTECTED]> wrote:
> On 5/20/05, Jochen K�hner <[EMAIL PROTECTED]>
wrote:
>
> >
QFileInfo Info(* it.current());
> >
>
> {
> >
>
>
for (QStringList::Iterator i = rom_extensions.begin(); i !=
> > rom_extensions.end();
> >
> >
{
> >
>
>
if(Info.extension(false).lower() == *i)
> >
>
>
{
> >
>
>
GameName = Info.baseName(false);
> >
>
>
bRomFound = true;
> >
>
>
break;
> >
>
>
}
> >
>
>
}
> >
>
> }
> >
> >
> > This procedure get all the amiga disk images. But the
Problem is, that I
> > need only one if the File name is for Exampe:
"Giana 01.adf" "Giana 02.adf"
> > "Giana 03.adf" or "Summer1.adf"
"Summer2.adf".
> >
> >
> >
> > I need one filename (as best without the number) and a
counter how many
> > files ther are
> >
> > Like: fnm = "Giana 0" , counter =
3 Fnm="Summer" counter = 2
> >
> >
>
> Here is a solution, its not difficult but its not easy.
>
> If all the files have names of the format
> <game name><optional
whitespace><numerics>.adf
> Then you need to have a variable outside the loop which you
initialize
> to null that tracks the current <game name>.
>
> Inside the loop where you get a file name you scan it from
the end
> backwards starting with the character preceeding
".adf" until you find a
> non-numeric, non-whitespace character. This is the end of
the game name.
>
> If the string you have matches the current game name then
you increment
> the count of the # of files for this game. If it doesn't
then you know
> you've found
> all the files for the current game and you record it.
>
> Then you set the current game name to the new one, the file
count to 1 and get
> the next filename.
>
> All of this could be embedded in a method which returns the
next game name
> and the # of files it consists of. This would need to be in
a class
> which contains
> the file pointer and storage for the current game name
field. The current game
> name field holds the next game name which will be processed
when the file
> is read. This would be null for the 1st invocation after the
file is
> opened. There
> probably has to be an EOF indicator in the class as well.
> _______________________________________________
> mythtv-dev mailing list
> [email protected]
> http://mythtv.org/cgi-bin/mailman/listinfo/mythtv-dev
>
--
Thanks,
Devan Lippman <
[EMAIL PROTECTED]>
--
Thanks,
Devan Lippman <[EMAIL PROTECTED]>
