Mike Koponick wrote: > All, > > Thanks for all the help/information regarding this subject. > > I have found a solution that works in this case. > > The problem is that the "%" is a directive for printf. Since the "%" was > in the string, printf thinks it should be a directive. > > Since I had no need for the "%" in the output string, I removed it. > > I changed the check_log script with the following: > > OLD: > $ECHO "($count) $lastentry" > > NEW: > $ECHO "($count) $lastentry" | /bin/sed 's/%//' > > I'm sure there is probably a more efficient way of doing this, but it > was a quick fix for me. > I guess the easier way might be to escape the % in printf.
Regards James Turnbull -- James Turnbull <[EMAIL PROTECTED]> --- Author of Pro Nagios 2.0 (http://www.amazon.com/gp/product/1590596099/) Hardening Linux (http://www.amazon.com/gp/product/1590594444/) --- PGP Key (http://pgp.mit.edu:11371/pks/lookup?op=get&search=0x0C42DF40) ------------------------------------------------------- This SF.Net email is sponsored by xPML, a groundbreaking scripting language that extends applications into web and mobile media. Attend the live webcast and join the prime developer group breaking into this new coding territory! http://sel.as-us.falkag.net/sel?cmd=lnk&kid=110944&bid=241720&dat=121642 _______________________________________________ Nagios-users mailing list Nagios-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/nagios-users ::: Please include Nagios version, plugin version (-v) and OS when reporting any issue. ::: Messages without supporting info will risk being sent to /dev/null
