Colin Alston wrote:
On 2008/08/27 05:22 PM Dave Israel wrote:

Normally, I don't participate in this sort of thing, but I'm a sucker for a "there's more than one way to do it" challenge.

Aww come on, C gets way more "fun" than that ;)

#define _u8 unsigned char
#define _u32 unsigned long

int main(void) {
    _u32 ipn = 1089055123;
    _u8 ipa[3];
    _u8 oct = 0;


    for (oct=0; oct <4; oct++){
        ipa[oct] = (char)(
            (ipn & (0xFF000000 >> (8*oct))) >> (8*(3-oct))
        );
    }

    printf("%d.%d.%d.%d\n", ipa[0], ipa[1], ipa[2], ipa[3]);

    return 0;
}

Actually, who needs loops for that?

#include <stdio.h>

int main()
{
        unsigned i = 1089055123;
        printf("%d.%d.%d.%d\n",
(unsigned char)(((char*)&i)[3]),
(unsigned char)(((char*)&i)[2]),
(unsigned char)(((char*)&i)[1]),
(unsigned char)(((char*)&i)[0])
);
        return 0;
}


Robert

Reply via email to