Try something like this: pattern="(?'version'(\d+\.){3}\d+)"
That will get the entire version number. If you need more fine-grained
extraction you could try:
pattern="(?'major'\d+)\.(?'minor'\d+)\.(?'build'\d+)\.(?'revision'\d+)"
Of course, you should use whatever names make sense to your development
environment. In both cases you will match one or more digits followed by
a period three times and lastly one or more digits.
If you need to distinguish between that line and other similar lines
then you may need more context like:
pattern=" TEST_VERSION .*(?'version'(\d+\.){3}\d+)"
Here you match a space, followed by the string TEST_VERSION, followed by
another space, followed by zero or more characters, followed by the
version number. This last expression will not match lines that do not
contain TEST_VERSION in it.
> -----Original Message-----
> From: [EMAIL PROTECTED] [mailto:nant-users-
> [EMAIL PROTECTED] On Behalf Of Felice Vittoria
> Sent: Wednesday, December 08, 2004 9:14 AM
> To: Nant-Users (E-mail)
> Subject: [Nant-users] regex help
>
> Hey guys/gals,
>
> I'm using the regex task. This is more of a regular expression
syntax
> more of Nant's usage. I have the following string in one of my
files:
>
> Public Const TEST_VERSION As String = "Test Program 1.0.0.1"
>
> What do I enter for regex's pattern attribute so that I can get the
value
> 1.0.0.1 ?
>
> Thanks,
> Felice
>
>
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