>If you declare a variable in A.c file, and in B.c
>file (which is going to be part of the executable),
>you try to access that variable, your attempt will
>fail (compiler will give an error) unless you declare
that
>variable as extern in B.c. Of course if you include
the >declaration in A.H and include A.h in both A.c
and B.c >you will succeed. So, extern type is
mandatory
>where you are using a variable which is declared in a
>different scope. If you just declare a variable as
>extern but don't have the actual definition in one of
>the files in the excutable, the linker will throw an
>error.
Yeah u r correct only...
but, please try it practically...
its not giving any error ....
its same with & without extern type declaration..
please execute the attached file...
i had declared a variable "int i" in t1.c file..
and included in t2.c and im able to accessing the
variable "i" with & without the declaration of
"extern int i" in t2.c file....
Please execute and see whether i did telling correct
or not....
i had executed in Linux(gcc compiler)
Rgds
Madhukar
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int i;
fun()
{
i=10;
printf("fun: i:%d\n",i);
}
#include <stdio.h>
#include "t1.c"
extern int i; /* try with and with out this type declaration */
main()
{
fun();
printf("main: i:%d\n",i);
}
