From: Nitin Dubey [mailto:[EMAIL PROTECTED]
>On Fri, 24 Dec 2004 07:51:02 -0800 (PST), Angsumankar Kar
><[EMAIL PROTECTED]> wrote:
>> Please explain it:
>>
>> void main()
main returns int, not float, class foo or void.
>> {
>> int *p=258;
Here you declare a pointer, and initialise it to point to a piece of
memory described as '258'
This is likely to invoke (as you in fact do on the next line) undefined
behaviour. i.e. anything is possible. Perhaps you meant something like:
int q = 258;
int *p = &q
>> printf("%d %d",*(char *)p,*(char *)p++);
Here you try to read and write whatever happens to be at address '258' -
the fact you're attempting to do both between two sequence points again
invokes undefined behaviour. This is like the expression i = i++; - it
makes no sense in the context of C or C++.
>> }
>>
>> output:0,2
Any output is permitted for reasons explained above...
>i tried running this code on my pc but its giving segmentation
>fault........
.. and as someone else has tried, other possibilities are allowed.
>if its running on your system then compile it with
>printf("%d %d %d %d",*(char *)p,*(char *)p++, *(char*)p++,
>*(char*)p++);
This is also broken code (undefined behaviour - see comment about i =
i++; above)
>if it gives you output 0 2 1 0 then i think i know why its giving you
>this output.....
>please just check it out.
--
PJH
"The difference between genius and stupidity is that genius had its
limits."
- Albert Einstein
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