--- guru_bo <[EMAIL PROTECTED]> wrote:
>
>
> Question is
> #include<stdio.h>
> #include<conio.h>
>
> void main()
> {
>
> struct BIT
> {
> int op1:5, op2:12;
> char d1;
> int reg;
> }Bitfields;
>
> clrscr();
>
> printf("%d is the size of the
> structure",sizeof(Bitfields));
>
> }
>
> What is the output
>
> Ans is 6,
> My reasoning is
>
> Assuming int is 2 byte
>
> op1:5 - 1, nearest byte is 5 + 3 ..
> 1byte
> op2:12 - 2 bytes
> char d1 - 1 byte
> int reg - 1 byte //IT should be 2
>
> is it correct
> Guru
>
>
Its the sum 12+5 = 17 bits + 7 bits = 24 bits (3
bytes)
op1 + op2 = 3 bytes
char = 1 byte
int = 2 byte
The answer would be 6 bytes..
Rgds,
Ashwin
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