the answer is quite on expected lines:
when you add maximum value of an integer with itself again then you are going to get a number which is greater than an integer data type.hence you get an unexpected result.
coming to saecond swap stmt:
yor are accepting z as refernec so whatever value is there will be reflected back in the main pgm:
a=10;
b=10;
a=a+b=10+10=20;
a=a-b=20-10=10;
b=a-b=10-10=0;
b=a-b=10-10=0;
henmce we are getting z value as 0
Paul Herring <[EMAIL PROTECTED]> wrote:
Paul Herring <[EMAIL PROTECTED]> wrote:
From: harry potter [mailto:[EMAIL PROTECTED]
>hi vijay,
>
>This is the code for swapping:-
>
>void swap(int &a, int &b)
>{
>a=a+b;
>a=a-b;
>b=a-b;
>cout<<"\n a is"<<a<<"\n b is"<<b;
>}
This breaks in two instances:
#include <limits.h>
int x=y=INT_MAX, z=10;
//(1)
swap(x, y); // undefined behaviour
//(2)
swap(z, z); // z==0 after this call.
--
PJH
"...one of the main causes of the fall of the Roman Empire was that,
lacking zero, they had no way to indicate successful termination of
their C programs." - Robert Firth
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