From: suresh babu [mailto:[EMAIL PROTECTED]
>hi, i am suresh. in an interview i was asked to reverse two
>nibbles in a byte of data.
>
>the question is as follows. suppose a number is assigned to a
>character like
>
>char c=0x82 then, a function should be described such that it
>will return number as 0x28
>
>my way of approach is as follows
[snip]
>but in the above program, temp1 is taking one byte of memory n
>value stored in it is 02, but temp2 is taking 2 bytes of
>memory and storing value as FFF8 before shifting.
>
>i had tried this program using Turboc3 compiler
>
>pls suggest modification in my program r any other approach to
>solve this problem
Your compiler is using 'signed char' - you either need to find an option
to make it use 'unsigned char' or explicitly define it:
$ type c.c
#include <stdio.h>
unsigned char exch_nibbles(unsigned char c){
unsigned char temp1, temp2;
temp1=c & 0x0F; //to obtain last four bits
temp2=c & 0xF0; //to obtain first four bits
temp1=temp1 << 4; //shifting the last four bits to left
temp2=temp2 >> 4; //shifting the first four bits to right
printf("\nThe temp1 value after shifting is %x",temp1);
printf("\nThe temp2 value after shifting is %x",temp2);
return(temp2|temp1); //adding the bits
}
int main(void){
char c=0x82;
printf("\nThe exchanged value is %x",exch_nibbles(c));
return 0;
}
$ c
The temp1 value after shifting is 20
The temp2 value after shifting is 8
The exchanged value is 28
$
--
PJH
If Windows is the solution, can we please have the problem back?
unknown
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