thank you very much.
I have another question, in this case that I have a infected relationship,
can I get the query that return the node that has the most outgoing
infected link (this is the node that infect others the most)
I wrote a query but it takes a lot to return the answer.this is becuase i
start from all node "(infTime:*)". I want to know is there a way to get
query by starting from the "infected" relationship and get that query?
(infTime is a propety that for example infTime=10 shows the node get
infected in the time 10)
START x=node:person("infTime:*")
MATCH x-[r:infected]->()
WITH x, count(r) as fof
return fof, x
order by fof desc
limit 1
On Monday, January 6, 2014 3:23:12 PM UTC+3:30, Michael Hunger wrote:
>
> You would model those infected-by information relationships between the
> nodes, not as property containing a number.
>
> Then you can use variable length paths to do long and also circular
> matches in the graph.
>
> MATCH p=(n:Person {name:"Mina"})-[:INFECTED_BY*]->(m)
> RETURN path,m
>
> HTH
>
> Michael
>
> Am 06.01.2014 um 09:36 schrieb mina sh <[email protected] <javascript:>
> >:
>
> i want to get recursive query in neo4j with cypher.
> in dataset ,nodes has property "whom" that shows the node get infected by
> whom
> (for exmaple node[1] is infected by node[10].-> node(1).whom= 10 )
> i want to search the graph recurively from the node[1] to node [10] and
> recursively so on to reach to the first node that has a whom=0 .
>
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