Ah.. The humble where clause! Thanks Michael this works a charm. To answer
your question I will end up with about 20,000 nodes.
Would you expect this query to be performant at that size? Again assuming
each node could have a relationship to each other node, i.e. ~400,000,000
possible relationships. I understand there is a cap on the number of
relationships though.
On Wednesday, February 5, 2014 2:19:34 PM UTC, Michael Hunger wrote:
>
> Depends on how many cards you have, in general you can use:
>
> MATCH (card1:Card)-[r:DECK_INCIDENCE]-(card2:Card)
>
> where card1.name in {cardsA} and card2.name in {cardsB}
>
> RETURN r;
>
>
> Michael
>
> Am 05.02.2014 um 15:05 schrieb Ben Titmarsh <[email protected]<javascript:>
> >:
>
> Hi All,
>
> I'd like your help with a bit of Cypher that I am trying to write.
>
> I have two lists of Strings containing the name property of some of the
> nodes in my graph. For example:
>
> fromNodes: ["cardA","cardB"..."cardZ"]
>
> toNodes: ["card1","card2"..."card50"]
>
> I would like to run a query to find all of the relationships of type
> 'DECK_INCIDENCE' that exist between the nodes defined in fromNodes and
> toNodes, i.e. for each node in fromNodes the query should return 50
> relationships (assuming that there is a relationship between all nodes) *
> 26 nodes in fromNodes = 1300 relationships.
>
> I'm relatively new to Cypher, but have been using the following to
> retrieve one relationship between two specific nodes:
>
> MATCH (card1:Card {name:"cardA"})-[r:DECK_INCIDENCE]-(card2:Card
> {name:"card13"}) RETURN r;
>
> How can I extend this to return all of the relationships that I need
> without having to run 1300 queries?!
>
> Thanks!
>
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