I'm running embedded. How'd the code for core API be like?
2014년 7월 6일 일요일 오후 11시 28분 49초 UTC+9, Michael Hunger 님의 말:
>
> If you're running embedded anyway, then I'd use core API for this check,
> not cypher
>
> If you use cypher
>
> - use parameters
> - use match not where
>
> START n1=node({id1}), n2=node({id2})
>
> match (n1)-[:%s]-(n2)
>
> RETURN true
>
> Limit 1
>
> Or rather for 2.x
>
> match (n1)-[:%s]-(n2)
>
> Where id(n1)={id1} and id(n2)={id2}
>
> RETURN true
>
> Limit 1
>
> Sent from mobile device
>
> Am 06.07.2014 um 11:37 schrieb Frandro <[email protected] <javascript:>
> >:
>
> The following query is that I use to check existence of an edge between
> the two nodes, n1 and n2.
>
> It seems the query costs a lot.
>
> Is this optimized or not? Is there a better way to find it out?
>
> String query = String.format("START n1=node(%d), n2=node(%d) WHERE
> n1-[:%s]-n2 RETURN count(*) as count_edges", nodeId1, nodeId2, edgeType);
>
>
> ExecutionResult result = engine.execute(queryString);
> int countEdges = Integer.valueOf(result.columnAs("count_edges").next().
> toString());
>
> if (countEdges > 0)
> return true;
>
> return false;
>
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