That is exactly what I was looking for. Thanks a lot Micheal!! On Friday, November 14, 2014 7:57:38 PM UTC-6, Michael Hunger wrote: > > Use Labels ! and an index or constraint > > create index on :Label(name_id); > OR > create constraint on (a:Label) assert a.name_id is unique; > > *match(A:Label) * > *where A.name_id = '5250' * > *return size(**(A)-->()-->(:Label2)) + size(**(A)-->(:Label2)) as Q* > > > On Fri, Nov 14, 2014 at 8:33 PM, edo okati <[email protected] > <javascript:>> wrote: > >> Hello All, >> I am new to Neo4J, I am currently working on doing a POC on our data. I >> am working on a query but couldnt find a exact solution online. So posting >> a new thread here. Here is my requirement: >> >> *match(A)-->(B)-->(C) where a.name_id = '5250' return count(*) as QZ -- >> Resulted in 500* >> >> *match(A)-->(C) where a.name_id = '5250' return count(*) as QA -- >> resulted in 600* >> >> now, I have two results QZ and QA, how can I combine query 1 and 2 and >> get 1100 as output? >> >> Hope question is clear enough, any questions, please reply. >> >> -- >> You received this message because you are subscribed to the Google Groups >> "Neo4j" group. >> To unsubscribe from this group and stop receiving emails from it, send an >> email to [email protected] <javascript:>. >> For more options, visit https://groups.google.com/d/optout. >> > >
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