Try this:
MATCH (a:Person{name:1})-->(b)-->(c)-->(d)
with collect(DISTINCT b) as nodesDist1, collect(DISTINCT c) as
nodesDist2,collect(DISTINCT
d) as nodesDist3
RETURN nodesDist1,
filter(n in nodesDist2 WHERE NOT n in nodesDist1) as
nodesDist2,
filter(n in nodesDist3 WHERE NOT n in nodesDist1 OR n in
nodesDist2) as nodesDist3
On Wed, Apr 13, 2016 at 8:52 AM, Kamilos <k19me...@gmail.com> wrote:
> hello,
> I'm trying to compute the k-hop using cypher.
>
> The idea is the following :
> The nodes at distance 1 from start node should be marked "NodesDist1",
> then, nodes at distance 2 should be names "NodesDist2" but they should
> not be the same as "NodeDistance1".
> Again, the nodes at Distance 3, should be different than the in
> NodesDist1 and NodesDistance2. See Image for more clarifications.
>
>
> <https://lh3.googleusercontent.com/-8Add_nPhxMs/Vw3q9iMmuwI/AAAAAAAAAHc/x4vINs9bVa8aS1omuWxUbIn7uYwe3WH7gCLcB/s1600/untitled.png>
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> Just getting the nodes from the outgoing edges is not a good solution
> because the nodes from the outgoing edges may already been seen in, for
> instance, NodesDist1.
>
> So I need I a way to filter them.
>
>
> This is what i got from the moment. However the "where filter" is not
> working, apparatently i cannot do that ?
>
>
> MATCH (a:Person{name:1})-->b-->c
> with collect(DISTINCT(b.name)) as nodesDist1, collect(DISTINCT(c.name))
> as nodesDist2,
> where filter(x IN nodesDist2 WHERE not(x in nodesDist1)) as res return
> res");
>
>
> So I'm looking for a way to do this query in cypher.
>
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