Is x a group?

And why are there two directions between user and group? With the same rel-type

Von meinem iPhone gesendet

> Am 04.06.2016 um 14:31 schrieb 'tgomell' via Neo4j <[email protected]>:
> 
> In this Special case with a Limit of 20 accounts we have a resultset of 650 
> lines.
> 
> profile match (n:i636005417297252034)where n.type='person' with n limit 20  
> match 
> p=((n:i636005417297252034)-[:rel_member*0..]->(x:i636005417297252034)<-[:rel_member*0..]-(gg:i636005417297252034)-[:rel_member*0..]->(m))
>  where n.type="person" and m.type="person" and not  gg.sAMAccountName 
> contains '_term_' and not (n.department = m.department or n.name= "" or 
> m.name ="" or gg.grouptype="BuiltIn_Group" or gg.commonsid="1" or 
> gg.name="domain users") and not id(n) = id(m) return n.name , n.department, 
> m.name, m.department order by n.name
> 
> The distance between could be 20 hops.
> 
> The Domain is typical for Active direcory: we habe User -Members->Groups
> We want to identify Cluster of users over amount of Connections over the 
> Groups.
> 
> regards, Thomas
> 
> Am Samstag, 4. Juni 2016 12:10:11 UTC+2 schrieb Michael Hunger:
>> Also, what's the max distance between a user and a group? 
>> 
>> what does your domain model look like? 
>> 
>> why do you have once (:Person)-[:rel_member]->(group) 
>> and once (group)-[:rel_member]->(person) ?? 
>> 
>> why do you need x in between ? you never use it 
>> 
>> match 
>> p=((n:Person:i636005417297252034:ProcessGroups)-[:rel_member*0..]->(x:Group???:ProcessGroups:i636005417297252034)<-[:rel_member*0..]-(gg:Group:ProcessGroups:i636005417297252034)-[:rel_member*0..]->(m:Person:ProcessGroups:i636005417297252034))
>>  
>> WHERE not id(n) <> id(m) AND n.department <> m.department and 
>> return n.name , n.department, m.name, m.department, collect (distinct 
>> gg.name) 
>> order by n.name 
>> 
>> In general I'd turn this into 
>> 
>> for all groups of label: :i636005417297252034 is there a var-length path to 
>> a user with :Person:i636005417297252034, if so, return all other paths to 
>> all other users with :Person:i636005417297252034 
>> 
>> 
>> 
>> 
>> > Am 04.06.2016 um 11:58 schrieb Michael Hunger 
>> > <[email protected]>: 
>> > 
>> > Please share the EXPLAIN plan 
>> > 
>> > This explodes probably into billions or trillions of paths. 
>> > 
>> > Some ideas: 
>> > 
>> > turn .type properties into labels 
>> > create a label for all your conditions, e.g. :Process 
>> > 
>> > and use those labels instead: 
>> > 
>> > What type are M, GG and X ? 
>> > 
>> > What is the fan out across those types (min, max, avg) ? 
>> > 
>> > How many results are returned after it finishes? 
>> > 
>> > Michael 
>> > 
>> > Can you send this as ticket and your database to your Neo4j support 
>> > account? 
>> > Or share your db with me? 
>> > 
>> >> Am 04.06.2016 um 09:23 schrieb 'tgomell' via Neo4j 
>> >> <[email protected]>: 
>> >> 
>> >> We have a really complex question: 
>> >> 
>> >> We want to find the ammount of Groups over all paths between all users. 
>> >> From all User to all User. The Amount of users is 8.000 and the amount of 
>> >> all Groups is 15.000. This cypher request Needs days! Is there a way to 
>> >> make this faster? 
>> >> 
>> >> match 
>> >> p=((n:i636005417297252034)-[:rel_member*0..]->x<-[:rel_member*0..]-gg-[:rel_member*0..]->(m))
>> >>  
>> >> where n.type="person" 
>> >> and m.type="person" 
>> >> and not  gg.sAMAccountName contains '_term_' 
>> >> and not (n.department = m.department 
>> >> or n.name= "" 
>> >> or m.name ="" 
>> >> or gg.grouptype="BuiltIn_Group" 
>> >> or gg.commonsid="1" 
>> >> or gg.name="domain users") 
>> >> and not id(n) = id(m) 
>> >> return n.name , n.department, m.name, m.department, collect (distinct 
>> >> gg.name) 
>> >> order by n.name 
>> >> 
>> >> Best regards, Thomas 
>> >> 
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