On Friday, June 22, 2012 2:52:34 PM UTC-7, [email protected] wrote:
>
> I bought one of Threeneurons (mike?) dekatron spinner kits to play with 
> some ideas. I'm new tubes in general. Anyway, the dekatron puts out about a 
> 50-60 volt "pulse" at NDX. I am trying to drop that closer to 5v but at 
> least less than 10v. I tried using a voltage divider made of 2 resistor 
> going from the NDX output to ground but this stops the dekatron movement. 
> Can anyone offer some advice.
>  
>

The pulse isn't 50V. Its limited by the little LED to whatever the forward 
drop of that LED is. ~2V (but biased 50V above ground; 50V to 52V). All the 
cathodes, are biased 50V above ground, and that's what you're seeing on 
your voltmeter.  If you want to interface it to some other circuit, try 
using an optocoupler:

http://www.allelectronics.com/make-a-store/item/4N33/OPTOISOLATOR-DARLINGTON-OUTPUT/1.html

http://www.vishay.com/docs/81865/4n32.pdf

Replace the current LED with the diode leg of the optocoupler. On the other 
side you have an electrically isolated darlington transistor (if you use 
the one above). Connect its collector to your low voltage logic supply. 
Connect the emitter to a resistor (between 2.2K and 10K), and ground the 
other leg of resistor. You should get a pulse off that emitter. 

A warning about optocouplers, they have a spec called current transfer 
ratio. For a regular transistor type, that could be between 20% to 50%. For 
darlington types is over 100%. The spinner current will only be ~300uA. If 
you use a regular transistor type, the output current will be only 60 to 
150uA. To see 5V across a resistor, the resistor needs to be at least 82K. 
That's kinda high, unless you're interfacing to 4000 CMOS.




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