For a MOSFET, there is no static drive-current except for a few nanoamps of leakage, which can usually be ignored. The gate-drive-current is whatever is needed to slew the gate-source capacitance (aka input capacitance). Using i=Cdv/dt, you can calculate how much drive-current your gate-driver needs to provide. From the datasheet, you need at least 4.5V for the gate-voltage. If you want a turn-on time around 250nsec, you would need about 25mA. Remember this is not continuous current; it's just there when turning the MOSFET on or off.
Take note of the gate-charge graph (Fig 6 on the datasheet) if you are using more than 5V for the gate; it's a non-linear capacitance which is typical for MOS devices. If you really want to do an accurate assessment, a SPICE simulation is best though that might be overkill in this application. You can get-by with a smaller gate-driver, but that will increase your switching loss; it's a tradeoff. -- You received this message because you are subscribed to the Google Groups "neonixie-l" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To post to this group, send an email to [email protected]. To view this discussion on the web, visit https://groups.google.com/d/msgid/neonixie-l/f4a79860-effd-4837-a5bc-32aa0df19869%40googlegroups.com. For more options, visit https://groups.google.com/d/optout.
