I had to think a little about that one. The easiest way to drive them, is 
using an NPN, with an emitter resistor, and sending the input to the base. 
Then the emitter will follow the base. The emitter current will follow that 
signal, as a function of voltage across the emitter resistor. The collector 
is roughly the same as the emitter current, less the base current, which 
can almost be ignored. 

The ramp, on this circuit, is always negative, relative to the analog 
portion's common (AREF). Maximum signal, is most negative, relative to 
AREF. The bar length is roughly proportional to the current flowing thru 
them. So instead of driving the base, I tied that one to near AREF, and fed 
the signal to the emitter. But the emitter has a lower impedance, and needs 
more drive current. That's why I added the PNP, as an emitter follower. The 
signal is fed into the base of that PNP. Its emitter follows the input. The 
base of the HV NPN, is fixed at roughly two diode drops (~1.2V) higher than 
AREF. The voltage drop, then, across the 1K resistor between these two 
transistors, roughly equals the ramp voltage. The current then thru both, 
and thru the bargraph is roughly that voltage divided by 1K. I designed the 
integrator to peak at -5V (relative to AREF), with 1.5V in (or 150 F) from 
the LM34. That translates to 5mA, which will "peg", the IN-13.

I like the IN-13 over the IN-9, mostly because it uses less current. The 
aux cathode helps keep the bar at one end. Its no guarantee, however. A 
friend of mine has a simple IN-13 winker, which now has its glow floating 
around the tube. These are odd tubes, which are designed to partially glow. 
It jut looks like a recipe for cathode poisoning. 

On Friday, February 27, 2015 at 4:33:11 PM UTC-8, AlexTsekenis wrote:
>
> Very intriguing way of going about creating/tapping into a ramp signal to 
> drive the bargraph. Nice!
>
> Alex
>

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