It seems I shouldn't use t.getRequestURI() as a real URI, its getPath()
is much better.
Thanks
Max
On 04/06/2011 05:09 PM, Chris Hegarty wrote:
Hi Max,
You should take a look at how this is done in FileServerHandler.java [1]
( one of the httpserver tests in the regression library). I think it
does what you are trying to do.
-Chris.
[1]
http://hg.openjdk.java.net/jdk7/tl/jdk/file/9f08a221e5f2/test/com/sun/net/httpserver/FileServerHandler.java
On 04/ 6/11 05:02 AM, Weijun Wang wrote:
Hi Guys
I am writing a test that starts a small HttpServer, and I write my
HttpHandler like this:
static class MyHttpHandler implements HttpHandler {
private final URI root;
MyHttpHandler(String fileroot) {
root = new File(fileroot).toURI();
}
public void handle(HttpExchange t) throws IOException {
URI uri = root.resolve(t.getRequestURI());
...
Here, root is the root of the webserver, and when a request comes in,
I'd like to resolve the request URI to the real URI in a file system.
Unfortunately, t.getRequestURI() already returns an absolute URI (say,
"/"), so the result uri is the same of it. We all know the "/" in "GET
/" is in fact not an absolute URI.
What is the elegant way to resolve it? I'm now using
URI uri = root.resolve(t.getRequestURI().toString().substring(1));
but it looks so ugly.
Thanks
Max
