Ok, it works.
The result is 186:190:186:190:250:206. Would it be possible to have the same
result in hexadecimal ? If not, I can go with that.
Thank you
2009/8/5 Vincent Bernat <[email protected]>
>
> On Wed, 5 Aug 2009 10:13:41 +0100, François Dumont
> <[email protected]> wrote:
>
> > I tried ":".join("%02x" % ord(a) for a in HardwareAddress) but I got the
> > error "ord() expected a character, but string of length 6 found".
>
> Yes, try:
> ":".join("%02x" % ord(a) for a in HardwareAddress[0])
>
> I missed the fact that you got a tuple with a string, not just a string.
>
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