Hi,
"Sterne, Jason (Nokia - CA/Ottawa)" <[email protected]> wrote:
> Hi all,
>
> I'm pretty sure that this xpath (e.g. in a must statement) isn't
> correct:
>
> (A) ../container-a/list-b[name=*]/some-leaf
>
> and should just be this instead:
>
> (B) ../container-a/list-b/some-leaf
Assuming all list entries has a 'name', yes, it is the same.
> Or is the * an allowable wildcard for a key value in a predicate ?
"*" is syntactically legal, but is not a wildcard on all values of the
node; it is a wildcard for all nodes.
So if all list entries has a name, A will evaluate to the same nodeset
as B, since "name = *" is a node-set comparison, and the node "name"
will be present in the node set from "*" (node set comparisons are not
always intuitive; read the spec for all details ;-)
> I also had a question about whether the following "must" correctly
> checks that at least one entry exists in a-list.
>
> container c1 {
> leaf foo {
> must "a-list";
> type uint16;
> }
> list a-list {
> key "entry";
> leaf entry {
> type uint16;
> }
> leaf another-entry {
> type uint32;
> }
> }
> }
>
> I think I could also replace that must with the following:
> must "count(a-list) > 1";
> but does must "a-list"; achieve the same thing ?
Yes, but if the list is big, the simple "a-list" may be more
efficient, since "count()" will actually count all instances
(modulo existance of optimizations in the evaluator).
/martin
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