My mistake. As you both correctly pointed out, refcnt needs to be 1 for reclaim.
It is initialized with 2. So some must be doing an unref()/put() to make it 1.
On 8/4/17, Daniel Gryniewicz <d...@redhat.com> wrote:
> On 08/04/2017 01:14 PM, Pradeep wrote:
>> Hello,
>>
>> I'm hitting a case where mdcache keeps growing well beyond the high
>> water mark. Here is a snapshot of the lru_state:
>>
>> 1 = {entries_hiwat = 100000, entries_used = 2306063, chunks_hiwat =
>> 100000, chunks_used = 16462,
>>
>> It has grown to 2.3 million entries and each entry is ~1.6K.
>>
>> I looked at the first entry in lane 0, L1 queue:
>>
>> (gdb) p LRU[0].L1
>> $9 = {q = {next = 0x7fad64256f00, prev = 0x7faf21a1bc00}, id =
>> LRU_ENTRY_L1, size = 254628}
>> (gdb) p (mdcache_entry_t *)(0x7fad64256f00-1024)
>> $10 = (mdcache_entry_t *) 0x7fad64256b00
>> (gdb) p $10->lru
>> $11 = {q = {next = 0x7fad65ea0f00, prev = 0x7d67c0 <LRU>}, qid =
>> LRU_ENTRY_L1, refcnt = 2, flags = 0, lane = 0, cf = 0}
>> (gdb) p $10->fh_hk.inavl
>> $13 = true
>>
>> Lane 1:
>> (gdb) p LRU[1].L1
>> $18 = {q = {next = 0x7fad625c0300, prev = 0x7faec08c5100}, id =
>> LRU_ENTRY_L1, size = 253006}
>> (gdb) p (mdcache_entry_t *)(0x7fad625c0300 - 1024)
>> $21 = (mdcache_entry_t *) 0x7fad625bff00
>> (gdb) p $21->lru
>> $22 = {q = {next = 0x7fad66fce600, prev = 0x7d68a0 <LRU+224>}, qid =
>> LRU_ENTRY_L1, refcnt = 2, flags = 0, lane = 1, cf = 1}
>>
>> (gdb) p $21->fh_hk.inavl
>> $24 = true
>>
>> As per LRU_ENTRY_RECLAIMABLE(), these entry should be reclaimable. Not
>> sure why it is not able to claim it. Any ideas?
>>
>
> refcnt == 2 is not reclaimable. Reclaimable is refcnt == 1. It checks
> for 2 because it just took a ref. Unless you're actually processing
> that lane, and so seeing the ref taken during that processing, refcnt
> will be 3 when processing, and it won't be reclaimed.
>
> Daniel
>
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