Im making an article catalog and I need to query my session for just
my root articles and catalogs
I want to have an property there I can determite IsRoot or IsLeaf or
something so I can get only those without a parent, can I solve this
by using formula or something? Im thinking that this property will
only be used when querying so I will not have this property on my
actual object just when searching.
Here are my current mapping:
<class name="IArticleCatalogItem" table="ArticleCatalogItem">
<id name="Id" type="System.Guid" unsaved-
value="00000000-0000-0000-0000-000000000000">
<generator class="guid" />
</id>
<joined-subclass name="ArticleCategory">
<key column="Id" />
<property name="Name" type="string" access="field.camelcase-
underscore" not-null="true" />
<many-to-one name="Parent" class="ArticleCategory"
access="field.camelcase-underscore" not-null="false" />
<set name="Items" access="field.camelcase-underscore"
inverse="false" cascade="all-delete-orphan">
<key column="ParentId" foreign-
key="FK_ArticleCategory_CategoryItem"/>
<one-to-many class="Hogia.Business.IArticleCatalogItem,
Hogia.Business"/>
</set>
</joined-subclass>
<joined-subclass name="Article">
<key column="Id"/>
<property name="ArticleNumber" type="string"
access="field.camelcase-underscore" not-null="true" />
</joined-subclass>
</class>
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