I'm afraid it's not possible. But if you have the use case, why not create the mapping on Cat? It's easier if you don't go against the tool :-)
Diego On Wed, Feb 17, 2010 at 08:48, Dor Rotman <[email protected]> wrote: > Hello, > All the documentation I see regarding HQL left joins work this way: > > from Eg.Cat as cat > left join cat.Kittens as kitten > > What if the mapping between cat and kitten doesn't exist, but there is > a mapping between kitten and cat? > I'd like to run this query: > > from Eg.Cat as cat > left join Kittens as kitten on kitten.cat > > Would that be possible? > > Thanks. > > -- > You received this message because you are subscribed to the Google Groups > "nhusers" group. > To post to this group, send email to [email protected]. > To unsubscribe from this group, send email to > [email protected]<nhusers%[email protected]> > . > For more options, visit this group at > http://groups.google.com/group/nhusers?hl=en. > > -- You received this message because you are subscribed to the Google Groups "nhusers" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/nhusers?hl=en.
