Yes!!!!
That do the trick.
Thank you very much
El 16/03/2010 13:03, Nexus escribió:
Try this
select cat, count(elements(co))
from Category cat left join cat.Courses co
where cat.ParentCategory is null
and (co.Visible=true or co.Visible is
null) and (co.Active=true or co.Active is null)
group by cat.Id, cat.ParentCategory,
cat.Site, cat.Name, cat.ImageFile
order by cat.Name asc
Kind regards
--
You received this message because you are subscribed to the Google Groups
"nhusers" group.
To post to this group, send email to [email protected].
To unsubscribe from this group, send email to
[email protected].
For more options, visit this group at
http://groups.google.com/group/nhusers?hl=en.
