You need to map the relationship between Person and Department in order to
use HQL left joins.
Diego
On Fri, Sep 17, 2010 at 06:58, alexey_baranov <[email protected]> wrote:
> Actualy, we need some hql surrogate of left join to find all Persons
> wich are not within Departments
>
> var result = sess.CreateQuery(@"
> select p
> from
> Person p, //Person need to be even
> if no department exists like with left join in sql
> Department d
> where
> p.Path like d.Path + cast(d.Id as String) + '/%'
> and d is null
> ")
>
> Thanks!
>
> PS: Department and Person are Entities extended Obj
>
> <?xml version="1.0" encoding="utf-8" ?>
> <hibernate-mapping xmlns="urn:nhibernate-mapping-2.2"
> assembly="Helpdesk" namespace="Helpdesk">
> <class name="Obj" discriminator-value="9">
> <id name="Id">
> <generator class="native" />
> </id>
> <discriminator column="Typee" type="Int32"/>
> <timestamp name="Modifed"/>
> <property name="Path" access="nosetter.camelcase-underscore" not-
> null="true"/>
> <property name="Name" column="Namee" not-null="true"/>
> <property name ="IsFolder" access="nosetter.camelcase-underscore"/
> >
> <property name="Note"/>
> <property name="Created" not-null="true"/>
> <many-to-one name="Owner" column ="Ownerr" />
> <many-to-one name ="Parent" access="nosetter.camelcase-underscore"/
> >
> <set name="Children" inverse="true">
> <key column="Parent"/>
> <one-to-many class="Obj"/>
> </set>
> <set name="Attachments" table="Obj_Attachments" cascade="save-
> update">
> <key column="Obj"/>
> <many-to-many column="Attachment" class="Filee"/>
> </set>
> </class>
> </hibernate-mapping>
>
> <?xml version="1.0" encoding="utf-8" ?>
> <hibernate-mapping xmlns="urn:nhibernate-mapping-2.2"
> assembly="Helpdesk" namespace="Helpdesk">
> <subclass name="Person" extends ="Obj" discriminator-value="0">
> <join table="Person">
> <key column="Id"/>
> <property name="FirstName"/>
> <property name ="SecondName"/>
> <property name="MiddleName"/>
> <property name="Email"/>
> <property name ="Phones"/>
> <!--
> <list name="Phones" table="Person_Phones">
> <key column="Ownerr"/>
> <index column="Indexx"/>
> <element column="Phone" type="String"/>
> </list>
> -->
> </join>
> </subclass>
> </hibernate-mapping>
>
> <?xml version="1.0" encoding="utf-8" ?>
> <hibernate-mapping xmlns="urn:nhibernate-mapping-2.2"
> assembly="Helpdesk" namespace="Helpdesk">
> <subclass name="Department" extends ="Obj" discriminator-value="32">
> <join table="Department">
> <key column="Id"/>
> <property name ="Address"/>
> </join>
> </subclass>
> </hibernate-mapping>
>
> Thanks!
>
> On Sep 17, 3:17 pm, alexey_baranov <[email protected]> wrote:
> > O, I see. We will rewrite query. Another question Is HQL may join
> > entities only if there is a refference-way from one to another?
> >
> > Thanks!
> >
> > On Sep 16, 11:17 pm, Fabio Maulo <[email protected]> wrote:
> >
> > > mmm the "path" mentioned in the exception message is not your property
> > > called "Path" but:
> > > left join Department <=== from where come Department ? it is a property
> of
> > > what ?
> > > The other error you will find is "on"; "on" is not HQL
> > > The other strange thing is: :rootDepartmentPath2 + '%' ; why don't do
> it in
> > > the parameter ?
> >
> > > before say "We try to use HQL first time and found exception" perhaps
> would
> > > be more productive to think : "We try to use HQL first time and
> perhpas we
> > > have not studied it enough".
> >
> > > On Thu, Sep 16, 2010 at 1:08 PM, alexey_baranov <[email protected]>
> wrote:
> > > > Hello!
> >
> > > > We try to use HQL first time and found exception. What does this
> "Path
> > > > expected for join!" means ? Path is a string not null property. Wwe
> > > > try to use this HQL to find Persons within Department rootDepartment
> > > > and not in subdepartments.
> >
> > > > Path expected for join! [
> > > > select p
> > > > from
> > > > Helpdesk.Person p
> > > > left join Department d on p.Path like d.Path +
> > > > cast(d.Id as String) + '/%'
> > > > where
> > > > p.Path like :rootDepartmentPath2 + '%'
> > > > and d.Path like :rootDepartmentPath2 + '%'
> > > > and d is null
> > > > ]
> >
> > > > Thanks.
> >
> > > > --
> > > > You received this message because you are subscribed to the Google
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> >
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> >
> > > --
> > > Fabio Maulo
>
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