probably you have the wrong schema linked to VisualStudio
<xs:element name="many-to-one">
<xs:complexType>
<xs:sequence>
<xs:element ref="meta" minOccurs="0" maxOccurs="unbounded" />
<xs:choice minOccurs="0" maxOccurs="unbounded">
<xs:element ref="column" />
<xs:element ref="*formula*" />
</xs:choice>
</xs:sequence>
<xs:attribute name="name" use="required" type="xs:string" />
<xs:attribute name="access" type="xs:string" />
<xs:attribute name="class" type="xs:string" />
<xs:attribute name="entity-name" type="xs:string" />
<xs:attribute name="column" type="xs:string" />
<xs:attribute name="not-null" type="xs:boolean">
</xs:attribute>
<xs:attribute name="unique" default="false" type="xs:boolean">
</xs:attribute>
<xs:attribute name="unique-key" type="xs:string" />
<xs:attribute name="index" type="xs:string" />
<xs:attribute name="cascade" type="xs:string" />
<xs:attribute name="outer-join" type="outerJoinStrategy">
</xs:attribute>
<xs:attribute name="fetch" type="fetchMode">
</xs:attribute>
<xs:attribute name="update" default="true" type="xs:boolean">
</xs:attribute>
<xs:attribute name="insert" default="true" type="xs:boolean">
</xs:attribute>
<xs:attribute name="optimistic-lock" default="true" type="xs:boolean">
</xs:attribute>
<xs:attribute name="foreign-key" type="xs:string" />
<xs:attribute name="property-ref" type="xs:string" />
<xs:attribute name="*formula*" type="xs:string" />
<xs:attribute name="lazy" type="laziness">
</xs:attribute>
<xs:attribute name="not-found" default="exception" type="notFoundMode">
</xs:attribute>
<xs:attribute name="node" type="xs:string" />
<xs:attribute name="embed-xml" default="true" type="xs:boolean">
</xs:attribute>
</xs:complexType>
</xs:element>
On Tue, Nov 9, 2010 at 2:38 PM, naasking <[email protected]> wrote:
> I have intellisense enabled, and "formula" does not appear as an
> option for many-to-one, only for "property" elements. This is entity
> references itself, so I don't think that will work.
>
> Sandro
>
> On Nov 9, 12:15 pm, Fabio Maulo <[email protected]> wrote:
> > Have you tried the tag 'formula' and you have some problem ?
> >
> >
> >
> > On Tue, Nov 9, 2010 at 12:40 PM, naasking <[email protected]> wrote:
> > > I have a class that evolves in a very well-defined way, such that
> > > given an arbitrary entity, I can compute the primary key of the
> > > previous entity. I'd like the entity to be loaded as a node in a
> > > linked list, with each entity having a "Previous" property which is
> > > loaded lazily using this formula, so I can traverse the history if I
> > > like.
> >
> > > In other words, no direct reference to the previous entry is stored in
> > > the current entry, but a formula is available to compute the previous
> > > key. Can I load a many-to-one using a formula this way?
> >
> > > Sandro
> >
> > > --
> > > You received this message because you are subscribed to the Google
> Groups
> > > "nhusers" group.
> > > To post to this group, send email to [email protected].
> > > To unsubscribe from this group, send email to
> > > [email protected]<nhusers%[email protected]>
> <nhusers%[email protected]<nhusers%[email protected]>
> >
> > > .
> > > For more options, visit this group at
> > >http://groups.google.com/group/nhusers?hl=en.
> >
> > --
> > Fabio Maulo
>
> --
> You received this message because you are subscribed to the Google Groups
> "nhusers" group.
> To post to this group, send email to [email protected].
> To unsubscribe from this group, send email to
> [email protected]<nhusers%[email protected]>
> .
> For more options, visit this group at
> http://groups.google.com/group/nhusers?hl=en.
>
>
--
Fabio Maulo
--
You received this message because you are subscribed to the Google Groups
"nhusers" group.
To post to this group, send email to [email protected].
To unsubscribe from this group, send email to
[email protected].
For more options, visit this group at
http://groups.google.com/group/nhusers?hl=en.