Thanks mratsim, that makes sense. Without being picky, why does
type
Temp* {.borrow: '>' .} = distinct intwork if > cannot be borrowed ? To be consistent that should also fail.
Thanks mratsim, that makes sense. Without being picky, why does
type
Temp* {.borrow: '>' .} = distinct intwork if > cannot be borrowed ? To be consistent that should also fail.