Your code doesn't do anything like what you say you want to do; it simply
removes the "cat" item and adds a "dog" item, which of course goes at the end.
The OrderedTable API does not offer mutable access to the keys, so there's
really no way to do what you want. You could do something like this, but since
the hash value isn't updated it will most likely break when more items are
added to the table, so _don 't do this_:
import hashes, tables
type StringBox = ref object
s: string
proc box(s: string): StringBox = StringBox(s: s)
proc `$`(sb: StringBox): string = sb.s
#proc hash(sb: StringBox): Hash = hash(sb.s)
let catbox = "cat".box
var animals = {catbox: "woof", "cow".box: "moo", "opossum".box:
"hisssss"}.toOrderedTable
catbox.s = "dog"
echo $animals
Run
> what i thought i could do is split at that key, add the new key name and then
> append the other half of the split... i don't know how i'd go about doing
> this though
Seems simple enough:
import tables
var animals = {"cat": "woof", "cow": "moo", "opossum":
"hisssss"}.toOrderedTable
proc replaceKey[K, V](tab: OrderedTable[K, V], old, new: K):
OrderedTable[K, V] =
for (k, v) in tab.pairs:
result.add(if k == old: new else: k, v)
echo $replaceKey(animals, "cat", "dog")
Run
Note that, if the same key appears more than once, this will replace all
occurrences.
