Re: a proc returning void creates 1 arg, not 0: breaking generic code

[timothee]

@Dennis my bad I should've verified the D code I posted; with tuples though we 
have:
    
    
    import std.stdio:writeln;
    void fun(T...)(T n)
    {
        static foreach (x; n)
            writeln(x);
        writeln("L=", T.length);
    }
    void main(){
        import std.typecons:tuple;
        fun(tuple(1,2).expand); // L=2
        fun(tuple(1).expand); // L=1
        fun(tuple().expand); // L=0
    }
    

in any case, the previous answers make total sense regarding Nim's behavior.